Determine values of c and d for √which the equation √(3x-1) - √(cx + d) = 0 has no solution.
i added √(cx + d) to both sides and squared them..3x-1 = cx + d
rearranged to get 3x - cx = d + 1; then factored out x to get x(3 - c) = d + 1
then divided x = ( d + 1) / ( 3 - c) therefore c ≠ 3 what about d?
i'm not sure what question is asking when looking for c and d

answer: need picture of problem

step-by-step explanation:

the direct variation says that:

then the equation is of the form is given by:

            where k is the constant variation.

from the given table:

consider any value of x and m(x)=y

x = 2 and m(x)=y = 3

substitute these value in [1]; we have;

divide both sides by 2 we get;

⇒

check:

put x = -1 and m(x) = -1.5

substitute in the equation:

-1.5 = -1.5                   true

therefore, the function m(x) represents a direct variation

graph of this function as shown below: