Question 9 of 20
baz + 4y
2y
23
19
what is the solution ( az, v) to the system of equations above?

The solution (x,y) is asking you to solve for the values of x and y
Let's get started
3x+4y=-23
2y-x=-19
Let's set the second equation in x= to solve for y
2y-x=-19
-2y both sides
-x=-2y-19
÷-1 both sides
x=2y+19
plug into first equation
3 (2y+19)+4y=-23
distribute
6y+57+4y=-23
add
10y+57=-23
-57 both sides
10y=-80
÷10 both sides
y=-8
Let's plug in y into the second equation to figure out x
2 (-8)-x=-19
-16-x=-19
+16 both sides
-x=-3
÷-1 both sides
x=3

solution is (3,-8)

If you want to check if this is true plug it into the first equation

3x+4y=-23
3 (3)+4 (-8)=-23
9-32=-23
-23=-23
solution holds true hope that helps :)

The answer is e &