At how many points does the graph of the function below intersect the x-axis? y = 2x^2 - 7x + 7

0

No such point on graph.

Step-by-step explanation:

Given:

We are given quadratic equation. We need to find number of points where it cuts x-axis.

When graph cuts x-axis their y-value is 0

We will set the equation to 0 and solve for x

Using quadratic formula.

where, a=2 , b=-7 , c=7

The value of x is imaginary. So, y will not cut x-axis any any point.

Hence, No such point on graph which cut x-axis.

c. y = 1/4 x + 5

step-by-step explanation:

first, put the equation of the line on the graph into slope-intercept form

(y = mx + b):   y = -4x + 8

second, a perpendicular line has to have "an opposite/reciprocal slope" to the original slope. so, find the "m" value in your original equation (it's -4, right? )

original slope: m = -4   perpendicular slope: change the sign to its opposite and find the reciprocal ("flip" the number)

new slope is now positive (b/c the original slope was negative 4), and it's 1/4 (not the original slope of 4 or 4/1)