One leg of a right triangle measures 8inches and the hypotenuse 17 inches determine the length if the other leg

15 inches.
a^2 + b^2 = c^2    so        c^2 - a^2 = b^2

(17)^2 - (8)^2 = b^2

289 - 64 = b^2

225 = b^2   then you take the square root on both sides

15 = b

Answer: d. 39 cmin the diagram, the approximate length of the minor arc de is 39 centimetres.step-by-step explanation: the formula for the length of an arc in a circle is as displayed below.let the length of the minor arc de = xx = 2( pi )r × angle of sector / 360°from this, we will substitute the values given from the problem into the formula to obtain the length of the minor arc de.x = 2( pi )r × angle of sector / 360°r = radius = 25cmpi as an approximate value = 3.14angle of sector = 120°x = 2( 3.14 )( 25 ) × 120° / 360°x = 157 × 1 / 4x = 39.25x = 39 ( rounded to the nearest whole number as an approximate value )