Ajar contains several colors of jelly beans. there are red, green, black, and yellow jelly beans in the jar. you pick one jelly bean at a time, record what color you picked, and then replace the jelly bean. you do this 30 times and get the following results.

there are 5 red, 15 green, 7 black, 3 yellow.

a. 0.3
b. 0.30
c. 0.90
d. 0.10

Option D.

Step-by-step explanation:

The question is: which is the probability of selecting a yellow jelly bean?

The data that we have is that, at random selection, we got:

5 times red

15 times green

7 times black

3 times yellow.

This means that out of 5 + 15 + 7 + 3 = 30 attempts, in 3 of them we got a yellow jelly bean, then the probability can be calculated as:

P = (number of times we got a yellow bean)/(total number of attempts)

P = 3/30 = 0.10

the correct option is D

example 2 – simplify: step 1: completely factor both the numerators and denominators of all fractions. step 2: change the division sign to a multiplication sign and flip (or reciprocate) the fraction after the division sign; essential you need to multiply by the reciprocal. step 3 : cancel or reduce the fractions.

translate k to n and reflect across the line containing jk.