Question 1: car a began a journey from a point at 9 am, traveling at 30 mph. at 10 am car b started traveling from the same point at 40 mph in the same direction as car a. at what time will car b pass car a?

Let after t hours the distances D1 traveled by car A

 D1 = 30 t

Car B starts at 10 am and will therefore have spent one hour less than car A when it passes it.

After (t - 1) hours, distance D2 traveled by car B

 D2 = 40 (t - 1)

When car B passes car A, they are at the same distance from the starting point and therefore D1 = D2

 30 t = 40 (t - 1)

Solve the equation for t,

 30 t = 40t - 40

 10 t = 40

 t = 4

 Car B passes car A at = 9 + 4 = 1 pm.

The answer is 1 pm I know because I did the equation on paper it took me a minute

Idon’t exactly understand but i think dbc=rst