Twenty-one fish are swimming in an aquarium. eleven are removed, leaving 10 fish. which number is the additive inverse of the number of fish left?

−10

fish left = 10

Therefore, the additive inverse of the number of fish left is −10. The sum of a number and its additive inverse is 0.

10 + (−10) = 0  A is the answer

36/60

36/2=18

60/2=30

18/30

18/3=6

30/3=10

6/10

6/2=3

10/2=5

your final answer would be 3/5 of an

hope this !

a is the correct