Ajuggler has a bag containing three yellow balls, six green balls, two blue balls, and one red ball, all the same size. the juggler pulls a ball from the bag at random. then, without replacing it, he pulls out a second ball. what is the probability that the juggler first draws a green ball followed by a blue ball?

hello from mrbilldoesmath!

answer:

a(n) - a(n-1) -3

discussion:

this ones a bit interesting. given a(n) = 5 - 3n consider this:

a(n-1) = 5 - 3(n-1)

          = (5 - 3n) + 3             => but a(n) = 5 - 3n, the first term

          = a(n)   + 3                 => subtract 3 from both sides

a(n-1) -3 = a(n)  

or

a(n) - a(n-1) -3

you,

mrb

answer: dead jah

step-by-step explanation:

bullet + jah= dead jah