From 6 cards bearing the letters a, b, c, d, e, and f, two cards are drawn. find the probability that at least one of the cards drawn bears a vowel. note: (a, b) and (b, a) are considered to be different elements in the sample space.
a) 2/15
b) 3/5
c) 5/9

We use the complement rule of probability.
P(at least one vowel) = 1 - P(no vowel)
To solve for P(no vowel) = (4/6)(3/5) = 2/5; since there are 4 consonants out of 6 letters and we take the letters without replacement.

P(at least one vowel) = 1 - 2/5 = 3/5.
The answer is B.

The answer is B just tried it and it is correct. Hope this helps.

Yes, that is the correct formula. to solve this problem given the number of years, plug in the number of years for t and plug the whole thing into the