Asample of 4 different calculators is randomly selected from a group containing 16 that are defective and 30 that have no defects. what is the probability that at least one of the calculators is defective

0.168
0.160
0.819
0.832

The solution would be like this for this specific problem:

The probability that at least one of the 4 calculators in the sample is defective is complement of 0.168 so the answer is 0.832.

x = -2

y = 848

step-by-step explanation:

plug in the numbers

the direct variation says that:

then the equation is of the form is given by:

            where k is the constant variation.

from the given table:

consider any value of x and m(x)=y

x = 2 and m(x)=y = 3

substitute these value in [1]; we have;

divide both sides by 2 we get;

⇒

check:

put x = -1 and m(x) = -1.5

substitute in the equation:

-1.5 = -1.5                   true

therefore, the function m(x) represents a direct variation

graph of this function as shown below: