Aregular heptagon has a radius of approximately 27.87 cm and the length of each side is 24.18 cm. what is the approximate area of the heptagon rounded to the nearest whole number? recall that a heptagon is a polygon with 7 sides. 1,173 cm2 2,125 cm2 2,359 cm2 4,250 cm2

Answer-

The area of the heptagon will be 2125 cm²

Solution-

A regular heptagon is a combination of 7 equal isosceles triangles. So the area of the regular heptagon is equal to 7 times the area of the isosceles triangle.

From the attachment it can be followed that,

Base = 24.18 cm

Radius = 27.87 cm

Applying Pythagoras Theorem,

(As the perpendicular bisects the base in case of an isosceles triangle)

Then the area of the triangle is,

So, the area of the heptagon will be,