Find the zero of the function
f(x)=(0x-3)(x+4)

F(x) = (0x - 3)(x + 4)
         0x - 3 = 0  or  x + 4 = 0
             + 3 + 3           - 4  - 4
                0x = 3             x = -4
                 0     0
                  x = 0
f(x) = (0x - 3)(x + 4)
f(3) = (0(3) - 3)(3 + 4)
f(3) = (0 - 3)(7)
f(3) = (-3)(7)
f(3)= -21
(x, f(x)) = (3, -21)
or
f(x) = (0x - 3)(x + 4)
f(-4) = (0(-4) - 3)(-4 + 4)
f(-4) = (0 - 3)(0)
f(-4) = (0)(0)
f(-4) - 0
(x, f(x)) = (-4, 0)

Assuming there really is 0

Ithink it’s b because it say 3 plastic rings and all the balls