During a long drive, tony counted the number of pickups and sedans he saw driving in the opposite direction. after a while, he noticed that on average there were 5 sedans for every 2 pickups. at this ratio, how many sedans would he have counted if he had passed 18 pickups?

At this ratio, he would have counted 45 sedans if he had passed 18 pickups. The ratio between the pickups and the sedan is two by five, therefore he already has faced 9 times of this situation if he had already seen 18 pickups passed over. The number of sedans counted by him can be obtained by multiplying the sedans number of the ratio which is 5 with the number of the situation that had passed which is 9.

In all honesty, there really is no “work” per say to show. mainly it’s just using the process of elimination. the question is asking which domain(s) would be the most appropriate for the function c(n). n is the number of observed vehicles so right away, 1, 2, and 3 can be eliminated.why? 1, 2 start in the negatives and therefore it is impossible to observe negative cars. so, #4 would be the best answer to the given problem.