Sam said the square root of a rational number must be a rational number. jenna disagreed. she said that it is possible that the square root of a rational number can be irrational. who is correct and why?

Jenna is correct.

Step-by-step explanation:

We can prove this statement with help of two examples.

Since we know that 64 is the rational number.

And, the square root of 64 is .

Which is equal to 8 or -8.

And, they are integers, and we know that the integer are always a rational number.

Therefore is a rational number.

And, If we take a number 2 which is a rational number.

Since, when we do square root of 2, we get √2.

And, √2 is a irrational number.

Thus, we can say that we can obtain a rational or irrational number after doing the square root of rational number.

Therefore, Jenna is correct.

C is correct

Step-by-step explanation:

Jenna is correct because not all square roots are rational. An example is StartRoot 2 EndRoot = 1.414213 ellipsis

x =-.20752

step-by-step explanation:

4^(x+2)=12

4^(x+2)=12

take the log base 4 on each side

log 4 (4^(x+2) = log 4(12)

we know log b(a^y) = y log b (a)

(x+2) log 4(4) = log 4 (12)

x+2 = log 4 (12)

we know   logb c = loga c/loga b

we want to convert to base 10   so a = 10

by default, we do not write the 10   c = 4   and b = 10

log4 10 = log 12/log 4

log4 10 = log 12/ log 4

x+2 = log 12/ log 4

subtract 2 from each side

x +2 -2 = log 12/ log 4 -2

x = 1.79248125 -2

x =-.20752