Match the reasons with the statements in the proof to prove ab || dc , given that ad is parallel to bc and ad = cb .
given:
ad || bc
ad = cb
prove:
ab || dc
1. ad || bc, ad = cb (a. if lines are parallel, then alternate interior angles are equal.)
2. ac = ac (b. if alternate interior angles are congruent, then lines are parallel.)
3. 2 = 3 (c. cpcte)
4. acd = cab (d. reflexive property of equality)
5. 1 = 4 (e. sas)
6. ab || dc (f. given)

Given: and AD=CB

To Prove:

1. , AD=CB

Reason: Given

2. AC = AC

Reason: Reflexive Property of Equality

3.

Reason: If Lines are parallel, then Alternate Interior Angles are Equal).

4.

Reason: SAS

5.

Reason: CPCTE

6.

Reason: If Alternate Interior Angles are Congruent, then Lines are Parallel.

sorry can't

step-by-step explanation:

i googled though and something came up but it was in science langueage not common english sooo

let's add {f(x)=x+1}f(x)=x+1 and {g(x)=2x}g(x)=2x together to make a new function.

f(x)+g(x) =(x+1)+(2x)=x+1+2x=3x+1

let's call this new function hh. so we have:

{h(x)}={f(x)}+{g(x)}{=3x+1}h(x)=f(x)+g(x)=3x+1

we can also evaluate combined functions for particular inputs. let's evaluate function hh above for x=2x=2. below are two ways of doing this.

method 1: substitute x=2x=2 into the combined function hh.

h(x)

h(2)

​    

=3x+1

=3(2)+1

=7

​ since h(x)=f(x)+g(x)h(x)=f(x)+g(x), we can also find h(2)h(2) by finding f(2) +g(2)f(2)+g(2).

first, let's find f(2)f(2):

f(x)

f(2)

​    

=x+1

=2+1

=3

​  

now, let's find g(2)g(2):

g(x)

g(2)

​    

=2x

=2⋅2

=4

​  

so f(2)+g(2)=3+4=\greend7f(2)+g(2)=3+4=7.

notice that substituting x =2x=2 directly into function hh and finding f(2) + g(2)f(2)+g(2) gave us the same answer!