Mathematics, 21.01.2020 20:31 Chealyn
Find the zeros of the function f(x)=1/2cos 2x with interval -2pi,2pi]
Answers: 1
![\bf f(x)=\cfrac{1}{2}cos(2x)\qquad [-2\pi \ ,\ 2\pi ]\iff [0\ , \ 2\pi ]\\\\ -----------------------------\\\\ cos(2\theta)= \begin{cases} cos^2(\theta)-sin^2(\theta)\\ 1-2sin^2(\theta)\\ \boxed{2cos^2(\theta)-1} \end{cases}\\\\ -----------------------------\\\\](/tpl/images/0464/4775/47ef8.png)
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