consider the arithmetic series: 1 + 9 + 17 + 25 +
write a formula for the sum of the first n terms in this series.
a) 4n^2 - 3n
b) 6n^2 - 7n
c) 8n^2 - 5n
d) 10n^2 - n

The formula for the sum of n terms in an arithmetic progression is:
S = n/2 * (2a + (n-1)d)
Here, the common difference, d, is 8 and the first term, a, is 1. Substituting these into the formula, we get:

S = n/2 * (2*1 + 8(n - 1))
S = n + 4n² - 4n
S = 4n² - 3n
The answer is A.

What does i equal do u know