Find the intercepts of the following equation y=x^2+x-42

X intercepts are where y=0

0=x^2+1x-42
0=(x-6)(x+7)
set to zero
x-6=0
x=6

x+7=0
x=-7
x intercepts are (-7,0) and (6,0)

y intercept is where x=0
y=0^2+0-42
y=-42
y intercept is (0,-42)

x intercepts at (-7,0) and (6,0)
y intercept at (0,-42)

Ithink it is 7. 16