Arandom sample of voters is polled and 34 plan to vote for candidate a, 56 plan to vote for candidate b, and 12 are undecided. what inference can be made from this random sample? candidate a will most likely win the election. candidate b will most likely win the election. there is not enough information to make an inference. candidate a and candidate b will have the same amount of votes.

Candidate B is more likely to be elected because out of the sample, it had more votes than candidate A. It is safe to assume this because the number of undecided votes is quite small and not likely to go all to one candidate.

The inference that can be made from this random sample is:

Candidate B will most likely win the election.

Step-by-step explanation:

We are given that:

A random sample of voters is polled and 34 plan to vote for Candidate A, 56 plan to vote for Candidate B, and 12 are undecided.

Since from the simulation we could see that  more person voted for  the Candidate B and less for the candidate A.

Even if all the undecided person will vote for Candidate A then also the total number of votes for candidate A will be less.

( Since 12+34=46<56)

Hence, there are most chances that Candidate B will win.

Intersecting secant-tangent theorem states that if a tangent segment and a secant segment are drawn to a circle from an exterior point, then the square of the measure of the tangent segment is equal to the product of the measures of the secant segment and its external secant segment.so to break it down: 1. pq acts as the tangent and ps as the secant with an intersection at p.sr = 21rp = 3x + 3pq = 4x + 4following to equation: tangent squared = the two segments multiplied by each otherso (4x + 4) ^ 2 = (3x + 3) • (21) simplifies to 16x^2 - 31x - 47 = 0 or (16x - 47)(x + 1) x = -1 or x = 47/162. pq acts as the tangent and ps as the secant with an intersection at p (again! )sr = 16rp = xpq = 15(15) ^ 2 = 16 • x225 = 16xx = 225/163. the interesting chords are proportional to each other so a ratio is possible to set up: ap dp 10 3 + x = = —— = pc pb 8 xcross multiple to get 10x = (3 + x)(8)x = 12