Match the parabolas represented by the equations with their foci.
1. y=-x^2+4x+8
2. y=2x^2+16x+18
3. y=-2x^2+5x+14
4. y=-x^2+17x+7
5. y=2x^2+11x+5
6.y=-2x^2+6x+5
-pairs-
a. (-2.75, -10)
b. (2, 11.75)
c. (-4, -13.875)
d. (1.25, 17)

match numbers 1-6 with letters a-d i really need

Function 1

First step: Finding when is minimum/maximum
The function has a negative value hence the  has a maximum value which happens when . The foci of this parabola lies on .

Second step: Find the value of y-coordinate by substituting into which give

Third step: Find the distance of the foci from the y-coordinate
- Multiply all term by -1 to get a positive
- then manipulate the constant of y to get a multiply of 4

So the distance of focus is 0.25 to the south of y-coordinates of the maximum, which is

Hence the coordinate of the foci is (2, 11.75)

Function 2:

The function has a positive so it has a minimum

First step - 
Second step -
Third step - Manipulating to leave with constant of 1
- Divide all terms by 2
- Manipulate the constant of y to get a multiply of 4


So the distance of focus from y-coordinate is to the north of
Hence the coordinate of foci is (-4, -14+0.125) = (-4, -13.875)

Function 3:

First step: the function's maximum value happens when
Second step:
Third step: Manipulating
- Divide all terms by -2
- Manipulate coefficient of y to get a multiply of 4

So the distance of the foci from the y-coordinate is - south to y-coordinate

Hence the coordinate of foci is (1.25, 17)

Function 4: following the steps above, the maximum value is when and . The distance from y-coordinate is 0.25 to the south of y-coordinate, hence the coordinate of foci is (8.5, 79.25-0.25)=(8.5,79)

Function 5: the minimum value of the function is when and . Manipulating coefficient of y, the distance of foci from y-coordinate is to the north. Hence the coordinate of the foci is (-2.75, -10.125+0.125)=(-2.75, -10)

Function 6: The maximum value happens when and . The distance of the foci from the y-coordinate is to the south. Hence the coordinate of foci is (1.5, 9.5-0.125)=(1.5, 9.375)

1) (1 , -22) and (1 , 12) ⇔ (y + 5)²/15² - (x - 1)²/8² = 1

2) (-7 , 5) and (3 , 5) ⇔ (x + 2)²/3² - (y - 5)²/4² = 1

3) (-6 , -2) and (14 , -2) ⇔ (x - 4)²/8² - (y + 2)²/6² = 1

4) (-7 , -10) and (-7 , 16) ⇔ (y - 3)²/5² - (x + 7)²/12² = 1

Step-by-step explanation: I got this right on Edmentum.