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![\bf log_{{ a}}(xy)\implies log_{{ a}}(x)+log_{{ a}}(y) \\ \quad \\ % Logarithm of rationals log_{{ a}}\left( \frac{x}{y}\right)\implies log_{{ a}}(x)-log_{{ a}}(y)\\\\ -----------------------------\\\\ log_b(x)-[log_b(y)+log_b(z)]\implies log_b(x)-[log_b(yz)] \\\\\\ log_b\left( \cfrac{x}{yz} \right)](/tpl/images/0399/3349/14346.png)
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How can i express logbx-(logby+logbz) as a single log?...
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