Ashipment of ball bearings with a mean diameter of 25 mm and a standard deviation of 0.2 mm is normally distributed. by how many standard deviations does a ball bearing with a diameter of 25.6 mm differ from the mean? 0.6 1 2 3

You need to calculate how many times the required difference is of the standard deviation, i.e. the ratio difference / standard deviation.

These are the calculations:

Standard deviation = 0.2 mm

Difference between 25.6mm and the mean = 25.6mm - 25mm = 0.6 mm

Ratio difference / standard deviation = 0.6mm / 0.2 mm = 3.

Then, the answer is that a ball with a diameter of 25.6 mm differs 3 standard deviations from the mean.

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