Given the graph below, which of the following statements is true?
a. the graph represents a one-to-one function because every x-value is paired with only one y-value.
b. the graph represents a one-to-one function because it is defined for all x-values.
c. the graph does not represent a one-to-one function because it does not pass through the origin.
d. the graph does not represent a one-to-one function because the y-values between 0 and 2 are paired with multiple x-values.

The answer is D because it fails the horizontal line test, it is a function but not a one to one function. Other guy showed more work than I ever could read his explanation and thank him. Also don't report me for this someone commented for a letter answer and i'm just giving it.

The answer is D

the answer is (-4,-4)

hope this ! : d

the answer is:

the correct option:

b.

to solve the problem, we need to remember how to operate to simplify exponential expressions using the logarithms.

we are given the equation:

then, using placing logarith with base 7 on both sides of the equation, we have:

so, rounding the obtained result to two decimal places (nearest hundreth), we have:

hence, we have that the correct option:

b.

have a nice day!