In the pendulum formula , we use g = 9.8 m/s2 for the acceleration due to gravity on earth. but what about on mars? if an astronaut on the surface of mars swings a 1-meter long pendulum, and it has a period of 3.27 seconds, what is the acceleration due to gravity, g, on mars?

Acceleration would be 3.7 m/s² due to gravity on Mars.

Step-by-step explanation:

We use the pendulum formula :

T =

Where L = 1 n

T = 3.27 seconds

∴ 3.27 =

=

= 0.5207 =

= 0.2711 =

= g =

g = 3.68 m/s² or 3.7 m/s²

Acceleration would be 3.7 m/s² due to gravity on Mars.

the answer is 13

step-by-step explanation:

5*5=25

12*12=144

25+144=169

169^2=13