Mathematics, 24.12.2019 22:31 madisonsolis05

# Arectangle has a length 5 feet greater than its width. if both dimensions are increased by 2 feet, write an expression for the difference in the areas of the rectangle

Answers: 3

Answer from: bossdde

W

L = W +5

New dimensions:

L' = L+2 = W+5+2 = W +7

W' = W+ 2

A = W(W+5)

A' = (W+2)(W+7)

A' - A = (W+2)(W+7) - W(W+5)

= W^2 + 9W +14 - W^2 - 5W

= 4W + 14

L = W +5

New dimensions:

L' = L+2 = W+5+2 = W +7

W' = W+ 2

A = W(W+5)

A' = (W+2)(W+7)

A' - A = (W+2)(W+7) - W(W+5)

= W^2 + 9W +14 - W^2 - 5W

= 4W + 14

Answer from: Quest

I'm not sure exactly but my best guess would be 1/4

Answer from: Quest

describing distributions is one of the key skills you’ll need to earn a high score on the ap statistics exam. if you need proof of this, just flip through some past exam questions, which can be found at the collegeboard website. you’ll notice that the first free response question is almost always a question requiring you to look at a graph and describe it.

step-by-step explanation: just trying to get points sorry : (

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Arectangle has a length 5 feet greater than its width. if both dimensions are increased by 2 feet, w...

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