If the length of the side of a square is 3x-y, what is the area of the square in terms of x and y?

The Area of the given square = (9x² - 6xy + y²) units²

Step-by-step explanation:

Length of the side of square = 3x - y units

Now, The all sides of the square are congruent to each other therefore, The measure of each side of the square = 3x - y

We need to find the area of the square with the given side 3x - y

Now, The area of the square is given by :

Area = (Side)²

⇒ Area of the given square = (3x - y)²

⇒ Area of the given square = (3x - y) × (3x - y)

⇒ Area of the given square = 9x² - 3xy - 3xy + y²

⇒ Area of the given square = 9x² - 6xy + y²

Therefore, The Area of the given square = (9x² - 6xy + y²) units²

a) y = -3x +2

b) y = 1/2x -6

these 2 can be combined into one equation.

-3x +2 = .5x -6

8 = 3.5x

x = 8 / 3.5 = 2.2857142857

y = -3 * (8 / 3.5) +2

y = (-24 / 3.5) + 2

y = -4.8571428571

step-by-step explanation:

the answer is c.

step-by-step explanation: