In triangle xyz, m∠z > m∠x + m∠y. which must be true about △xyz?

m∠x + m∠z < 90°

m∠y > 90°

∠x and∠y are complementary

m∠x + m∠y < 90°

D)m∠X + m∠Y < 90°

Step-by-step explanation:

Given: In triangle XYZ, m∠Z > m∠X + m∠Y.

In a triangle the sum of the interior angles is 180 degrees.

m∠Z is greater than the sum of the angles X and Y.

Two angles cannot be equal to or greater than 90 degrees because the sum of the angles exceeds 180 degrees.

Therefore, the sum of the angles X and Y must be less 90 degrees.

So, answer is D)m∠X + m∠Y < 90°

well there are two answers for that.

1: you need 120 ones then that will equal up to 120.

2: you could also do one 100 and 2 tens.

those are the answers that i have thought of.

idk

step-by-step explanation: