Hunter raises beetles. in a square of compost 6 ft by 6 ft, he can have 500 beetles. how many beetles can he have if his square of compost has a side length that is four times longer?

If Hunter raises beetles in a square of compost with a size of 6 ft by 6 ft and having 500 beetles, and then you are to find the number of beetles with a side length that is four times longer, then you can solve this by ratio and proportion.

A = s²
A = 6²
A = 36 ft²

if s = 4*the original length, then the new area is 

A = 24²
A = 576 ft²

500 beetles/36 ft² = x number of beetles/576 ft²
x = 8,000 beetles

Answer: v= lwhstep by step explanation: length x width x heightl = 12kmw = 6kmh = 6km12 x 6 = 7272 x 6 = 432therefore your answer would be c) 432 km^3