Which is the general form of the equation of the circle shown? x2 + y2 + 4x – 2y – 4 = 0 x2 + y2 + 4x – 2y + 2 = 0 x2 + y² – 4x + 2y – 4 = 0

The equation of a circle with center at point (h, k) and radius of r units is given by


From the diagram, the center of the given circle is at points (-2, 1) and the radius is 3 units.

Therefore, the equation of the given by