What is the equation of the line, in point-slope form, that passes through the points (4, 8) and (2, -2)?

a-y + 2 = -5(x - 2)
b-y - 2 = -5(x + 2)
c-y + 2 = 5(x - 2)
d-y - 27 = 5(x + 2)

Point-slope form: y-(y-value) = m(x-(x-value))
Where m = slope
To find slope, we need ◇y/◇x. = (y2-y1)/(x2-x1)
For the points (4,8) & (2,-2)
Let's make the 1st pair: (x2,y2) and 2nd pair: (y1,x1)--> (8--2)/(4-2) = (8+2)/(4-2) = 10/2 or 5, so m=5
Now pick any of the two points and plug in to point-slope equation. They used point (2,-2) by looking at the options.
So y-(-2) = 5(x-2)--> simply to: y+2= 5(x-2)
Therefore [C] is the correct answer

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