What is the slope-intercept form of a line that passes through points (2, 11) and (4, 17)?
a) y= -3x -5
b) y= 3x -5
c) y= -3x + 5
d) 3x + 5

Slope = (17 - 11)/(4-2) = 6/2 = 3

y = mx + b
11 = 3(2) + b
11 = 6 + b
b = 5

equation
y =3x + 5

answer 
d. y = 3x + 5

Y=mx+b
m=slope
b=y intercept

find the slope first
the sloep of  the line that passes throught the 2 points (x1,y1) and (x2,y2) is
(y2-y1)/(x2-x1)
so the points (2,11) and (4,17)
(17-11)/(4-2)=6/2=3
slope is 3

y=3x+b
find b
subsitute a point
(2,11)
(x,y)
subsitute 2 for x and 11 for y
11=3(2)+b
11=6+b
minus 6 both sides
5=b

y=3x+5 is the equation

D is the answer

Hmmm i had this before , give me a sec

The answer should be c.