What is the vertex of the quadratic function f(x) = (x – 6)(x + 2)?

(2, -16)

Step-by-step explanation:

The vertex, by definition, is the max or min point of a parabola that is exactly halfway between the 2 zeros.  

We have our zeros at:

x - 6 = 0 so

x = 6 and

x + 2 = 0 so

x = -2

We have our zeros at (-2, 0) and (6, 0).  Half way in between those 2 x- values is the x-value 2.  If we sub in a 2 for x in the binomials they gave you, you will get the y-value that goes along with that x...which in turn will represent the y value of the vertex (it's actually the k value but...):

y = (2 - 6)(x + 2) and

y = (-4)(4) so

y = -16

Therefore, the vertex of the quadratic is (2, -16)

Step-by-step explanation:

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet

what are you trying to solve here

step-by-step explanation: