What is the vertex of g(x) = –3x2 + 18x + 2?

The vertex of g(x) is (3;29)

Step-by-step explanation:

The coordinates of the vertex for a cuadratic equation are defined as:

Xv = -b/2a

Yv = f(Xv)

Where b, and a correspond to the coefficients of the linear and cuadratic  terms respectively. In this particular case f(x) is represented by g(x).  

Then by replacing the coefficients a and b in the x-coordinate we obtain:

Xv = -18/ (2.-3) = -18 / -6 = 3

And by replacing Xv in g(x):

Yv = g(Xv) = -3(3)^2 + 18(3) + 2  

Yv = -27 + 54 + 2 = 29

Thus the vextex of g(x) is (3:29)

d) 30 units^2

area of rectangle = l × b

we know,

length = 10 unit

breadth = 3 unit

applying the formula,

= l × b

= 10 × 3

= 30 unit^2

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