Afair die will be rolled 12 times. what is the probability that 4 , 5 , or 6 is rolled less than 6 but more than 3 times

 P(4,5 or 6)=3/6=1/2 and we need to find
P(4 times or 5 times... getting 4,5 or 6) = P(4 times ...)+ P(5 times...)
=(1/2)^12 + (1/2)^12 = (1/2)^11

i'm not very sure if its correct. but, u can use this as your last resort. something is better than nothing. and let me know if its right.
 

Ibelieve that c. recording would work best.