What are the mean, median, and mode of the following data set?

3/4
2/5
1/10
3/4
1/4
a.
mean: 1/10, median: 1/10, mode: 3/4
b.
mean: 9/20, median: 1/10, mode: 3/4
c.
mean: 9/20, median: 2/5, mode: 3/4
d.
mean: 2/5, median: 4/9, mode: 3/4

C- mean: 9/20, median: 2/5, mode: 3/4

Step-by-step explanation:

I used process of elimination so it only took a minute, rather than adding all of them up and finding a common denominator.  

3/4 shows up twice while the rest show up once, its obviously the mode.

if you put them in order:

1/10 , 1/4 , 2/5, 3/4 , 3/4

you have 2/5 in the middle.

(And if you want to do the whole thing, an easier way to find the mean is changing them to decimals (.1, .25, .4, .75, .75) and changing them back to fractions once you have the answer is an easier way of doing it.

#15. square

step-by-step explanation:

because quadrilatural (idk how to spell it) means somthing that is not 3d or like, equal sides (or somthing like that   you know what i meanz)

hope this halps!

bai!

no oblique asymptote

step-by-step explanation:

to find the oblique asymptote of f(x)

here numerator has degree 1 and denomintor degree 2

degree of numerator < degree of denominator

hence there is no oblique asymptote

when the degree of the denominator > that of the numerator, we saw that the value in the denominator got so much bigger, so quickly,   giving us a horizontal asymptote of the x-axis. or we can write

f(x) = a polynomial of x + a proper fraction.

in this case only we have oblique asymptotes but not when numerator has less degree.