Arunning track in the shape of an oval is shown. the ends of the track form semicircles
what is the perimeter of the inside of the track? (π = 3.14)
40 points

This track is formed by 1 rectangle and 2 half a circle or 1 circle

Perimeter of a rectangle = 2 ( Length + With)
Perimeter of a circle = 2π. R

1st. Perimeter of te rectangle The width of the rectangle = 42 m & its length = 110 m so the perimeter of the rectangle = 2(42+110) = 2(152) = 304 m²

2nd.Perimeter of the circle = 2π. (21) [ 42 being the diameter so 21 m= R)
2.(3.14)(21) = 131.88 m²

TOTAL PERIMETER =  304 m² + 131.88 m² = 435.88 m²