Given a mean of 52.3 and a standard deviation of 1.8, what is the z-score of the value 51.8 rounded to the nearest tenth?

The z-score of a certain data point in the given statistical data is calculated through the equation,
                                           z-score = (x - m) / sd
where x is the data point, m is the mean and sd is the standard deviation. 
Substituting the known values,
                                           z-score = (51.8 - 52.3) / 1.8
                                           z-score = -0.277
Rounding the answer to the nearest tenth will give an answer of -0.3. 

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