Of the 10 contestants in a televised quiz competition, 2 were eliminated during this week’s show, and 2 more will be eliminated during next week’s show. how many groups of 6 remaining contestants are possible a week from now? assume that the show airs on the same day every week.

There are 210 ways of groups of 6 in a week from now.

Step-by-step explanation:

Since we have given that

Number of contestants in a televised quiz competition = 10

Number of contestants were eliminated in this week's show = 2

Number of contestants were eliminated in next week's show = 2

So, We have to choose groups of 6 remaining contestants which are possible a week from now .

For this we will apply " Combination Method":

So, Number of ways possible for groups of 6  will be given as

Hence , there are 210 ways of groups of 6 in a week from now.

There are 210 ways of groups of 6 in a week from now.

Step-by-step explanation:

Since we have given that

Number of contestants in a televised quiz competition = 10

Number of contestants were eliminated in this week's show = 2

Number of contestants were eliminated in next week's show = 2

So, We have to choose groups of 6 remaining contestants which are possible a week from now .

For this we will apply " Combination Method":

So, Number of ways possible for groups of 6  will be given as

Hence , there are 210 ways of groups of 6 in a week from now.

so what is the question

step-by-step explanation:

logv3(x+2)=1

rewrite in exponential form:

logb(x) = y is equal to b^y =x

b = 3, y = 1

now solve for x:

3^1 = x+2)

x = 3-2

x = 1

see the picture for the graph.