What is the equation of a line that is perpendicular to y=3x-2 and passes through the point (6 8) answers

The perpendicular equation is y = -1/3x + 10.

You can find this by first realizing that perpendicular lines have opposite and reciprocal slopes. So since it starts at 3 we flip it and make it a negative and the new slope is -1/3. Now we can use that and the point to get the y intercept using slope intercept form.

y = mx + b

8 = (-1/3)(6) + b

8 = -2 + b

10 = b

And now we can use our new slope and new intercept to model the equation.

y = -1/3x + 10

true

step-by-step explanation: