In the following function defined by an equation in the form y=ax^2+bx+c, identify the values of a, b, and c.

y= -x^2+5x

a) a=0, b=5, c=0
b) a= -1, b=5, c=0
c) a= 1, b=5, c=0
d) a=5, b= -1, c=0

B) a= -1, b=5, c=0

Step-by-step explanation:

This is a quadratic equation.

From the form given y=ax^2+bx+c, it can be deduced that a, b and c are the coefficient of x^2, x and the constant respectively.

As such, when y=ax^2+bx+c is compared with

y= -x^2+5x,

a = -1, b = 5 and c = 0

Hence option B) a= -1, b=5, c=0 is right.

the number of possible outcomes that do not show a 1 on the first spinner and show the number 4 on the second spinner is 2.

spinner 1 spinner 2

1                     1

1                     2

1                     3

1                     4

2                   1

2                   2

2                   3

2                   4   = not 1, and 4

3                   1

3                   2

3                   3

3                   4 = not 1, and 4

only 2 outcomes have passed the given condition.

step-by-step explanation: