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a portion of a circle is removed resulting in figures a and b. the area of figure a equals one third the area of figure b.

what is the area of the figure b?

use 3.14 to approximate for π .

enter your answer to the nearest tenth in the box.

Solution (1) using angles of sectors:

Area of A = pi r^2  x 90/360 = 4.9

Area of B = pi r^2 x 270/360 = 14.2 

Check:  Area of A/B = 4.9/14.72 = 1/3 (as given)

Solution (2) using given info:

Area of B + Area of A = area of circle

Area of B + 1/3 Area of B =  3.14 * (2.5)^2 = 19.625

4/3 Area of B = 19.625

Area of B = 3/4 * 19.625

Area of B = 14.72

Area of A = 1/3 * 14.72 = 4.9

There is more solutions to this problem , like polar coordinate integration , and so on. for more just request. 

Im sorry but what on

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