Which solution to the equation 3/2g+8=g+2/g^2-16 is extraneous?
a g = –4
b g = –4 and g = 16
c neither g = –4 nor g = 16
d g = 16

A) g = –4

Step-by-step explanation:

The given equation is:

We cross multiply to get:

Expand to get:

Group similar term;

The domain of the given function is

Therefore g=-4 is an extraneous is an extraneous solution

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step-by-step explanation:

pleaze mark brainliest!

none of the above.

for one of the equations to be used in the process, there has to be a term in the equation since squared is .

since there is only a term in the first equation, we cannot derive a from completing the square.

solving with completing the square