The measure of arc qs is (4x-18)° what is the value of x?

Option C. 49.5°

Step-by-step explanation:

In the given figure arc QS is the diameter of the circle.

Angle formed at semicircle is 90°.

Therefore angle formed at center T will be 180°(∠QPS = 180° which is 2×∠QRS)

Now it is given arc QS = (4x - 18)° and equal to 180°

4x - 18 = 180

4x = 180 + 18 = 198

4x = 198

x = 198/4 = 49.5°

So the answer is 49.5°

the answer is d

step-by-step explanation:

y+3=-4(x-2)

y+3=-4x+8

  -3         -3  

y=-4x+5