Francine has a picture with a length 5/3 its width. she wants to enlarge the picture to have an area of 375 in2. what will the dimensions of the enlarged picture be? model the scenario and solve. then, explain in at least one sentence your solution and include the reasonableness of your solution.

Let the width of the picture be x, the length will be given by 5/3x.
This implies that the area of the picture will be given by:
Area=length*width
Area=x*5/3x=375
5/3x^2=375
multiplying both sides by 3/5 we get:
x^2=225
getting the square root of both sides we get:
sqrt(x^2)=sqrt22
x=15
Thus the width will be x=15 in
the length will be:
15*5/3
=25 inches.
Therefore the dimension will be:
15 in by 25 in

You would need a laid out graph for this but could you provide a picture of just a graph? i can give stepssolve for y.subtract 4xdivide by -1 (opposites)graph slope intercept formcheck each point to see if it’s on the graph