If the velocity of a car on a timed test drive on an airfield is given by the function:
v= 24t - 3t(squared)
where v is in m/s and t is in seconds
starting from rest, the car comes to rest again after 8 seconds. how far has it travelled during that time?

The graph of the car's speed is a piece of an inverted parabola,
that cuts the time axis at zero and at 8 sec. 

The distance the car travels during that 8 seconds is the area
between the parabola and the time axis.  If you intend to calculate
it, then I'm afraid you're going to need to integrate the speed function.

           V = 24t - 3t²

Distance = integral of (24t - 3t²), evaluated from zero to 8 seconds.

Integral of (24t - 3t²) =

             t²/2 - 3t³/3  =  12t² - t³

Evaluated between zero and 8 seconds, the integral is

             12(8²) - (8)³ =

               768 - 512  =  256 meters .

hope it is correct if not i'm srry i tried to

Google it that might work