Line ab passes through points a(–6, 6) and b(12, 3). if the equation of the line is written in slope-intercept form, y = mx + b, then m = – and b = –6–55 6.

(-6,6)(12,3)
slope(m) = (y2 - y1) / (x2 - x1) = (3 - 6) / (12 - (-6) = -3 / 18 = -1/6

y = mx + b
slope(m) = -1/6
use either of ur points (12,3)x = 12 and y = 3
now sub and find b, the y int
3 = -1/6(12) + b
3 = -12/6 + b
3 = -2 + b
3 + 2 = b
5 = b

so ur slope(m) = -1/6 and ur y int (b) = 5