When is g(x) = 0 for the function g(x) = 5⋅2^3x + 4?

never

Step-by-step explanation:

g(x)=0 will never be a solution to the function above. If you plug in the options of 1, 0, and 4, none of them make zero.

see explanation

step-by-step explanation:

since the sequence is geometric there is a common ratio r between consecutive terms, that is

r = 4 ÷ - 2 = - 2

r = - 8 ÷ 4 = - 2

r = 16 ÷ 8 = - 2

the next term - 13 must be incorrect as it should be - 32 for the sequence to be geometric.

the first 4 terms are therefore geometric with common ratio r = - 2