An isosceles triangle has an area of 175 ft^2. if the base is 16 ft, what is the length of each leg? round the answer to the nearest tenth.

A=bh/2

h=2A/b

h=2*175/16

h=21.875

h^2=s^2-(b/2)^2

h^2=s^2-b^2/4

h^2=(4s^2-b^2)/4

4h^2=4s^2-b^2

4s^2=4h^2+b^2

s^2=(4h^2+b^2)/4

s=√((4h^2+b^2)/4), since h=21.875 and b=16

s=√542.515625

s≈23.3 ft

Omg that is a big question and weird words and i’m only 5