If you were to use the substitution method to solve the following system, choose the new equation after the expression equivalent to x from the first equation is substituted into the second equation.

−x + 5y = 1
2x + 4y = −4
2(5y − 1) + 4y = −4
2(−5y + 1) + 4y = −4
2x + 4(−5y + 1) = −4
2x + 4(5y − 1) = −4

2(5y-1) + 4y = −4

Step-by-step explanation:

−x + 5y = 1   > first equation

2x + 4y = −4  > second equation

we solve the first equation for x

−x + 5y = 1

To solve for x we need to get 'x' alone

Add x on both sides

5y = 1+x

Now subtract 1 from both sides

x= 5y - 1

Plug in 5y-1 for x in the second equation

2x + 4y = −4

2(5y-1) + 4y = −4

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