Suppose the line of the best fit is being found for some data points that have an r-value of 0.885. if the mean of the x-coordinates is 5,768, and the mean of the y-coordinates is 8.112, what is the slope of the line to three decimal place.
a)1.245< < < < nvm thats the correct answer
b)0.803
c)0.629
d)1.589

a)1.245

Step-by-step explanation:

There is a mistake in the question, the corrected version is:

"the standard deviation of the x-coordinates is 5.768 and the standard deviation of the y-coordinates is 8.112"

The equation of a line, in general terms, is:

y = a + b*x

where b is its slope and a is its y-intercept.

In a regression, the slope can be computed as follows:

b = r * standard deviation of the y-coordinates / standard deviation of the x-coordinates = 0.885*8.112/5.768 = 1.245

hope it you

step-by-step explanation:

sin(7pi/6 - pi/3)  

= sin(7pi/6 - 2pi/6)  

= sin(5pi/6)  

= sin(pi - pi/6)  

= sin(pi/6)  

= 1/2  

sin 7pi/6 - sin pi/3  

= sin (pi + pi/6) - sin pi/3  

= -sin pi/6 - sin pi/3  

= -1/2 - sqrt(3)/2  

= -(1+sqrt(3))2

linear pair postulates